A) \[3\]
B) \[4\]
C) \[5\]
D) \[6\]
Correct Answer: B
Solution :
[b] \[f(2+x)=f(2-x)\] \[f'(2+x)=-f'(2-x)\] When \[x=0,\]then \[f'(2)=0\]. When \[x=-1,\]then \[f'(1)=-f'(3)=0\]. When \[x=\frac{-3}{2},\]then \[f'\left( \frac{1}{2} \right)=-f'\left( \frac{7}{2} \right)=0.\] \[\therefore \,\,\,\,\,f'\left( \frac{1}{2} \right)=f'(1)=f'(2)=f'(3)=f'\left( \frac{7}{2} \right)=0\]. Using Rolle's Theorem on f(x), minimum number of roots of \[f''(x)=0\]is 4.You need to login to perform this action.
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