A) \[\frac{14}{15}\Omega \]
B) \[\frac{7}{15}\Omega \]
C) \[\frac{4}{3}\Omega \]
D) \[\frac{5}{6}\Omega \]
Correct Answer: A
Solution :
[a] B and D are symmetrical w.r.t O and A \[\Rightarrow \] equipotential \[\therefore \] Circuit becomes \[\therefore \,\,\,{{R}_{OA}}=\frac{(R)\,(7R/8)}{R+\frac{7R}{8}}=\frac{7R}{15}=\frac{14}{15}\,\,\Omega \]You need to login to perform this action.
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