A) \[{{[Co{{F}_{4}}]}^{2-}}\]
B) \[{{[Co{{(NCS)}_{4}}]}^{2-}}\]
C) \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}\]
D) \[{{[CoC{{l}_{4}}]}^{2-}}\]
Correct Answer: C
Solution :
Higher the oxidation state of the metal, greater the crystal field splitting energy. In options [a], [b] and [d], \[Co\]is present in \[+2\] oxidation state and in [c] it is present in \[+3\] oxidation state and hence has a higher value of CFSE.
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