2. Sample Papers
  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main - Mock Test - 1

  • question_answer
    Naturally occurring boron consists of two isotopes whose atomic weights are \[10.01\] and\[11.01\]. The atomic weight of natural boron is\[10.81\]. Calculate the percentage of isotope with atomic weight \[11.01\] in natural boron.

    Answer:

    80


You need to login to perform this action.
You will be redirected in 3 sec spinner