A) \[a=3,b=2\]
B) \[a=3,b=3\]
C) \[a=1,b=1\]
D) \[a=2,b=2\]
Correct Answer: C
Solution :
[c] : Since, points (3, 3), (h, 0) and (0, k) are collinear, so one point will lie on the line joining the other two points i.e.,\[y-0=\frac{k-0}{0-h}(x-h)\] \[\therefore \]\[3=-\frac{k}{h}(3-h)\](\[\because \] (3, 3) lies on the line) \[\Rightarrow \frac{3}{h}+\frac{3}{k}=1\Rightarrow \frac{1}{h}+\frac{1}{k}=\frac{1}{3}\] comparing with\[\frac{a}{h}+\frac{b}{k}=\frac{1}{3}\], we get a = 1, b = 1
You need to login to perform this action.
You will be redirected in
3 sec
