JEE Main & Advanced Sample Paper JEE Main - Mock Test - 1

  • question_answer
    \[\frac{1+\sin A-\cos A\text{ }}{1+\sin A-\cos A}=\]

    A) \[\sin \frac{A\text{ }}{2}\]         

    B) \[\cos \frac{A\text{ }}{2}\]

    C) \[\tan \frac{A\text{ }}{2}\]         

    D) \[\cot \frac{A\text{ }}{2}\]

    Correct Answer: C

    Solution :

    [c]:\[\frac{1+\sin A-\cos A}{1+\sin A+\cos A}\] \[=\frac{2{{\sin }^{2}}\frac{A}{2}+2sin\frac{A}{2}\cos \frac{A}{2}}{2{{\cos }^{2}}\frac{A}{2}+2\sin \frac{A}{2}\cos \frac{A}{2}}\] \[=\frac{2\sin \frac{A}{2}\left( sin\frac{A}{2}+\cos \frac{A}{2} \right)}{2\cos \frac{A}{2}\left( \cos \frac{A}{2}+sin\frac{A}{2} \right)}=\tan \frac{A}{2}\]


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