JEE Main & Advanced Sample Paper JEE Main - Mock Test - 1

  • question_answer
    If the circles \[{{(x-1)}^{2}}+{{(y-3)}^{2}}={{r}^{2}}\] and \[{{x}^{2}}+{{y}^{2}}-8x+2y+8=0\] intersect in two distinct points, then

    A) \[2<r<8\] 

    B) \[r=2\]

    C) \[r<2\]             

    D) \[r>2\]

    Correct Answer: A

    Solution :

    [a] : Centres : \[{{C}_{1}}(1,3),{{C}_{2}}(4,-1),\] Radii:\[{{r}_{1}}=r,{{r}_{2}}=\sqrt{16+1-8}=3\] \[{{C}_{1}}{{C}_{2}}=\sqrt{9+16}=5,|{{r}_{1}}-{{r}_{2}}|<{{C}_{1}}{{C}_{2}}<{{r}_{1}}+{{r}_{2}}\] \[\Rightarrow \]\[|r-3|<5<r+3\] \[\therefore \]\[r>2,|r-3|<5\Rightarrow r-3<5,r<8\] \[\therefore \]\[2<r<8\].


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