A) \[\frac{-h}{eE{{t}^{2}}}\]
B) \[\frac{-mh}{eE{{t}^{2}}}\]
C) \[\frac{-h}{eEt}\]
D) \[\frac{-eEt}{h}\]
Correct Answer: A
Solution :
[a] : Here, \[u=0,a=\frac{eE}{m}\] \[\therefore \]\[v=u+at=0+\frac{eE}{m}t\]de-Broglie wavelength, \[\lambda =\frac{h}{mv}=\frac{h}{m(eEt/m)}=\frac{h}{eEt}\] Rate of change of de-Broglie wavelength \[\frac{d\lambda }{dt}=\frac{h}{eE}\left( -\frac{1}{{{t}^{2}}} \right)=\frac{-h}{eE{{t}^{2}}}\]
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