A) \[B=\frac{{{\mu }_{0}}\pi C}{4{{r}^{2}}}({{r}^{2}}-{{a}^{2}})\]
B) \[B=\frac{{{\mu }_{0}}C}{4{{r}^{2}}}({{r}^{4}}-{{a}^{4}})\]
C) \[B=\frac{{{\mu }_{0}}\pi C}{4r}({{r}^{2}}-{{a}^{2}})\]
D) \[B=\frac{{{\mu }_{0}}C}{4r}({{r}^{4}}-{{a}^{4}})\]
Correct Answer: D
Solution :
[d]: Given : Current density\[J=C{{r}^{2}}\] For a region a < r < b. The Amperian loop is a circle labelled as 1You need to login to perform this action.
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