A) \[1:2\]and \[2:1\]
B) \[7:2\]and \[1:2\]
C) \[2:1\]and \[2:1\]
D) \[2:7\]and \[2:1\]
Correct Answer: B
Solution :
[b] Spinel structure: \[{{A}^{+2}}{{B}_{2}}^{3+}{{O}_{4}}^{2-}\] Number of \[{{A}^{+2}}\] ions \[=\frac{1}{8}\times TV's=\frac{1}{8}\times 8=1\] (1 T.V is occupied) Number of \[{{B}^{+3}}\] ions \[=\frac{1}{2}\times OV's=\frac{1}{2}\times 4=2\] (2 OV's are occupied) Number of TV's unoccupied \[=8-1=7\] Number of OV's unoccupied \[=4-2=2\] \[\therefore \,\,\left( \frac{TV}{OV} \right)\] unoccupied \[=7:2\] \[\left( \frac{TV}{OV} \right)\]occupied \[=1:2\]
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