A) Halogenation of \[C{{H}_{4}}\]
B) Nitration of benzene
C) An alkene prepared by \[{{E}_{1}}CB\] mechanism
D) An alkene prepared by \[{{E}_{1}}\] mechanism
Correct Answer: A
Solution :
[a] (1) It shows \[{{1}^{{}^\circ }}\] isotope effect since \[(C-H)\] and \[(C-D)\] bonds broken in the halogenation of \[C{{H}_{4}}\] and \[C{{D}_{4}}\] \[{{H}_{3}}C-H\xrightarrow[hv]{C{{l}_{2}}^{+}}{{H}_{3}}C-Cl+HCl\] \[{{D}_{3}}C-D\xrightarrow[hv]{C{{l}_{2}}^{+}}{{D}_{3}}C-Cl+DCl\] (2) It does not show \[1{}^\circ \] isotope effect since no \[(C-H)\] or \[(C-D)\] bond breaks in first R.D.S. (3) It does not show \[1{}^\circ \] isotope effect. In \[E1cB,\] the reaction rate does not depend on the breaking of \[(C-H)\] or \[(C-D)\] bond but depends on the leaving \[{{X}^{\Theta }}\] ion in the second step.You need to login to perform this action.
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