A tripeptide (X) on hydrolysis gives three amino acids: |
\[(N{{H}_{2}}-\underset{R}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-COOH)\] |
\[(N{{H}_{2}}-\underset{R'}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-COOH)\] |
\[N{{H}_{2}}-\underset{R''}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-COOH)\] |
(X) on reaction with \[N{{H}_{2}}N{{H}_{2}}\] gives a dipeptide (Y) and amino acid . |
A) \[C-A-B\]
B) \[B-A-C\]
C) \[A-B-C\]
D) \[B-A-C\]
Correct Answer: A
Solution :
[a] (A is also C-terminal amino acid) From the above reaction, it is clear that the amino acid [c] is N-terminal. Hence the sequence is \[(C\to A\to B)\]. \[C-A-B\]You need to login to perform this action.
You will be redirected in
3 sec