A) \[{{H}_{2}}O\]
B) \[{{H}_{2}}S\]
C) \[{{H}_{2}}Se\]
D) \[{{H}_{2}}Te\]
Correct Answer: D
Solution :
As the size of anion(M) increases \[M-H\]bond strength decreases, so release of \[{{H}^{+}}\] becomes easier. Thus \[{{H}_{2}}Te\]is most acidic because size of \[Te\] is highest.You need to login to perform this action.
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