JEE Main & Advanced Sample Paper JEE Main - Mock Test - 21

  • question_answer
    A particle is shifted from A to B and then from B to C where A, B and C are the midpoints of the corresponding faces of a cube of side 2 m. If a force \[\vec{F}=\left( 3\hat{i}+4\hat{j}-5\hat{k} \right)N\] N is continuously acting on the particle,
     
     
    (i) Work done from A to B is 7 J                        
    (ii) Work done from B to C is 2 J
    (iii) Work done A to C is 6 J                               
    (iv) Force F, is a conservative force
    The correct statements are
     

    A) (i) and (iv)    

    B) (i) and (ii)           

    C) (iii) and (iv)         

    D) (ii) and (iv)

    Correct Answer: A

    Solution :

    [a] \[\overrightarrow{OA}=\hat{i}+\hat{k},\] \[\overrightarrow{OB}=2\hat{i}+\hat{j}+\hat{k},\] \[\overrightarrow{OC}=\hat{i}+2\hat{j}+\hat{k},\] \[\Rightarrow \,\,\,\,\,\,\,\,\overrightarrow{AB}=\overrightarrow{OB}-\overrightarrow{OA}=\hat{i}+\hat{j}\]\[\overrightarrow{BC}=\overrightarrow{OC}-\overrightarrow{OB}=\hat{j}-\hat{i},\,\,\overrightarrow{AC}=\overrightarrow{OC}-\overrightarrow{OA}=2\hat{j}\] \[{{W}_{AB}}=\vec{F}.\overrightarrow{AB}=7,\,{{W}_{BC}}=\vec{F}.\overrightarrow{BC}=1,\,\,{{W}_{AC}}=\vec{F}.\overrightarrow{AC}=8\]A constant force is always a conservative force.   


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