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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 21

  • question_answer
    Find the charge in coulombs required to convert \[0.2\text{ }mole\] \[V{{O}_{3}}^{2-}\]to \[V{{O}_{4}}^{3-}\].

    A) \[1.93\times {{10}^{4}}\]          

    B) \[9.65\times {{10}^{4}}\]

    C) \[1.93\times {{10}^{5}}\]           

    D)        \[9.65\times {{10}^{5}}\]

    Correct Answer: A

    Solution :

    Charge \[=0.2\times 1\]Faraday \[=0.2\times 96500\]coulombs \[=19300=1.93\times {{10}^{4}}\]coulombs


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