A) \[5.14\times {{10}^{21}}\]unit cells
B) \[1.28\times {{10}^{21}}\]unit cells
C) \[1.71\times {{10}^{21}}\]unit cells
D) \[2.57\times {{10}^{21}}\]unit cells
Correct Answer: D
Solution :
Since in \[NaCl\]type structure 4 formula units form a cell. \[58.5\text{ }g\]of \[NaCl=6.023\times {{10}^{23}}\]atoms \[1g\] of \[NaCl=\frac{6.023\times {{10}^{23}}}{58.5}\]atoms atoms constitute 1 unit cell \[\therefore \,\,\frac{6.023\times {{10}^{23}}}{58.5}\] atoms constitute \[=\frac{6.023\times {{10}^{23}}}{58.5\times 4}=2.57\times {{10}^{21}}\] unit cells.
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