A) \[{{H}_{2}}O\]
B) \[{{H}_{2}}S\]
C) \[{{H}_{2}}Se\]
D) \[{{H}_{2}}Te\]
Correct Answer: D
Solution :
As the size of anion(M) increases \[M-H\]bond strength decreases, so release of \[{{H}^{+}}\] becomes easier. Thus \[{{H}_{2}}Te\]is most acidic because size of \[Te\] is highest.
You need to login to perform this action.
You will be redirected in
3 sec
