A) 0
B) 1
C) 2
D) 1/2
Correct Answer: D
Solution :
[d]: Given limit \[=\underset{x\to 0}{\mathop{\lim }}\,\frac{(1+x)ln(1+x)-x}{{{x}^{2}}}\] \[=\underset{x\to 0}{\mathop{\lim }}\,\frac{ln(1+x)}{2x}\] (By L' Hospitals Rule) \[=\underset{x\to 0}{\mathop{\lim }}\,\frac{1}{2}\ln {{(1+x)}^{\frac{1}{x}}}=\frac{1}{2}\]You need to login to perform this action.
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