A) \[{{x}^{3}}\]
B) \[{{x}^{2}}\]
C) \[({{a}^{2}}+{{b}^{2}}+{{c}^{2}})\]
D) None of these
Correct Answer: B
Solution :
[b]: Clearly, (Applying\[{{R}_{1}}\to {{R}_{1}}+{{R}_{2}}+{{R}_{3}}\]) \[={{x}^{2}}({{a}^{2}}+{{b}^{2}}+{{c}^{2}}+x)\] Hence \[\Delta \]is divisible by \[{{x}^{2}}\] as well as by x.You need to login to perform this action.
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