A) \[{{Z}_{11}}(A)=32\,\,{{Z}_{11}}(B)\]
B) \[32\,{{Z}_{11}}(A)=\,\,{{Z}_{11}}(B)\]
C) \[{{Z}_{11}}(A)=\,16\,{{Z}_{11}}(B)\]
D) \[16\,{{Z}_{11}}(A)=\,{{Z}_{11}}(B)\]
Correct Answer: A
Solution :
[a] Since \[{{Z}_{1}}=\frac{{{\mu }_{av}}}{{{\lambda }_{A}}},\]You need to login to perform this action.
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