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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 23

  • question_answer
    A projectile is projected from a level ground making an angle \[\theta \] with the horizontal (x direction). The vertical (y) component of its velocity changes with its x co-ordinate according to the graph shown in figure. Calculate \[\theta \]. Take g \[g=10\,m{{s}^{-2}}\].

    A) \[45{}^\circ \]           

    B) \[60{}^\circ \]                  

    C) \[30{}^\circ \]                 

    D)        \[75{}^\circ \]

    Correct Answer: A

    Solution :

         [a] From graph, \[{{u}_{y}}=10m/s\] \[{{\text{v}}_{y}}\] becomes zero when \[x=\frac{Range}{2}\] \[\therefore \] Range \[=20\text{ }m\] \[\therefore \,\,\,\,\,\frac{2{{u}_{x}}{{u}_{y}}}{g}=20\]        


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