A) \[\frac{{{I}_{0}}}{4}\]
B) \[\frac{3{{I}_{0}}}{4}\]
C) \[{{I}_{0}}\]
D) \[\frac{{{I}_{0}}}{2}\]
Correct Answer: A
Solution :
[a] Optical path diff. \[\Delta x=(\mu -1)t\] Phase diff. \[\Delta \phi =\frac{2\pi }{\lambda }\Delta x\] \[=\frac{2\pi }{600\times {{10}^{-9}}}\times 0.4\times 5\times {{10}^{-6}}\] \[\Delta \phi =\frac{20\pi }{3}\] \[{{I}_{res}}={{I}_{0}}{{\cos }^{2}}\left( \frac{\Delta \phi }{2} \right)={{I}_{0}}{{\cos }^{2}}\left( \frac{10\pi }{3} \right)\] \[\left[ {{I}_{res}}=\frac{{{I}_{0}}}{4} \right]\]
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