A) \[<<{{10}^{9}}Hz\]
B) \[<<{{10}^{5}}Hz\]
C) \[>>{{10}^{9}}Hz\]
D) None of these
Correct Answer: A
Solution :
[a] Using \[\frac{1}{{{f}_{carrier}}}<<RC\] We get time constant, \[RC=1000\times {{10}^{-12}}={{10}^{-9}}s\] Now \[v=\frac{1}{T}=\frac{1}{{{10}^{-9}}}={{10}^{9}}Hz\] Thus the value of carrier frequency should be much less than \[{{10}^{9}}Hz,\] say\[100kHz\].
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