JEE Main & Advanced Sample Paper JEE Main - Mock Test - 23

  • question_answer
    The transverse displacement of a string is given by\[y(x,t)=0.06sin\left( \frac{2\pi }{3}x \right)\cos (120\pi t)\] where x and y are in m and t in s. The length of the string is 1.5 m and its mass is 3.0 x 10~2 kg. Determine the tension in the string (in Newton).



You need to login to perform this action.
You will be redirected in 3 sec spinner