A) \[Xe{{F}_{4}}\]
B) \[Xe{{F}_{6}}\]
C) \[Xe{{F}_{2}}\]
D) \[Xe{{O}_{3}}\]
Correct Answer: C
Solution :
\[Xe{{F}_{2}}\]:
\[Xe{{F}_{4}}\]:
\[Xe{{F}_{6}}\]:
\[Xe{{O}_{3}}\]:
Hence \[Xe{{F}_{2}}\] has maximum no. of lone pairs of electrons.
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