• # question_answer The angle between the lines $2x=3y=-z$and $6x=-y=-4z$ is A) $\frac{\pi }{6}$             B) 0 C) $\frac{\pi }{3}$             D) $\frac{\pi }{2}$

Solution :

[d]: The d.rs of the lines are $\frac{1}{2},\frac{1}{3},-1$and$\frac{1}{6},-1,-\frac{1}{4}$or 3, 2.-6 and 2.-12,-3 $3\times 2+2\times (-12)+(-6)(-3)=0.$ $\therefore$$\theta =\frac{\pi }{2}$

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