JEE Main & Advanced Sample Paper JEE Main - Mock Test - 24

  • question_answer
    The coefficient of thermal conductivity of copper is nine times that of steel in the composite cylindrical bar shown in the figure. What will be the temperature at the junction of copper and steel

    A) \[75{}^\circ C\]            

    B)        \[67{}^\circ C\]

    C) \[33{}^\circ C\]            

    D)        \[25{}^\circ C\]

    Correct Answer: A

    Solution :

    \[\operatorname{Temperature}\,\,of\,\,interface\,\theta =\,\,\frac{{{K}_{1}}{{\theta }_{1}}{{l}_{2}}+{{K}_{2}}{{\theta }_{2}}{{l}_{1}}}{{{K}_{1}}{{l}_{2}}+{{K}_{2}}{{l}_{1}}}\] It is given that \[{{\operatorname{K}}_{Cu}}=9\,{{K}_{s}}.So\,\,if\,\,{{K}_{S}}=\,\,{{K}_{1}}=K\] then \[{{\operatorname{K}}_{Cu}}={{K}_{2}}=9K\] \[\Rightarrow \,\,\,\,\,\theta =\frac{9K\times 100\times 6+K\times 0\times 18}{9K\times 6+K\times 18}=\frac{5400\,K}{72\,K}=\,\,75{}^\circ C\]


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