JEE Main & Advanced Sample Paper JEE Main - Mock Test - 24

  • question_answer
    In an electromagnetic wave, the amplitude of electric field is 1 V/m. The frequency of wave is \[5 \times  1{{0}^{14}}Hz\]. The wave is propagating along z-axis. What will be the average energy density of electric field, in\[joule/{{m}^{3}}\]?

    Answer:

    \[\left( 2.21\times 1{{0}^{-}}^{12} \right)\]


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