A) Square
B) Parallelogram which is not a square
C) Trapezium
D) Rhombus which is not a square
Correct Answer: C
Solution :
[c] \[{{z}^{4}}-{{z}^{3}}+2{{z}^{2}}-z+1=0\] \[\Rightarrow \,\,\,\,({{z}^{2}}+1)({{z}^{2}}-z+1)=0\] \[\Rightarrow \,\,\,\,z=\pm i,\,\,\frac{1\pm \sqrt{3}i}{2}\] From the figure, it is clear that the quadrilateral is a trapezium (ABCD).You need to login to perform this action.
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