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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 24

  • question_answer
    The oxidation number of S in the compound \[KAI{{(S{{O}_{4}})}_{2}}.12{{H}_{2}}O\]is

    A) +4

    B)          +2

    C) +6                   

    D) +2.5

    Correct Answer: C

    Solution :

    [c] : Since water is a neutral molecule, the sum of the oxidation numbers of all the atoms in water is taken as zero. \[KAl{{(S{{O}_{4}})}_{2}}.12{{H}_{2}}O\] \[+1+3+2x-16=0\Rightarrow x=+6\]


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