A) II > I > III > IV
B) I > III > II > IV
C) III > I > II > IV
D) I > II > III > IV
Correct Answer: B
Solution :
[b]: In
lone pair on \[-N{{H}_{2}}\]remains more available for donation and its conjugate acid is resonance stabilised thus, it is most basic. Between \[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}\]and \[{{(C{{H}_{3}})}_{2}}NH,\]the later is more basic because of the presence of two alkyl groups which facilitate the donation of lone pair of electrons. 
is least basic as the lone pair of N is involve in resonance. 
Thus, the correct order of basicity is I > III > II > IV.
You need to login to perform this action.
You will be redirected in
3 sec
