question_answer

The correct order of basicity?s of the following compounds is

A) II > I > III > IV

B) I > III > II > IV

C) III > I > II > IV

D) I > II > III > IV

Correct Answer: B

Solution :

[b]: In lone pair on \[-N{{H}_{2}}\]remains more available for donation and its conjugate acid is resonance stabilised thus, it is most basic. Between \[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}\]and \[{{(C{{H}_{3}})}_{2}}NH,\]the later is more basic because of the presence of two alkyl groups which facilitate the donation of lone pair of electrons.  is least basic as the lone pair of N is involve in resonance. Thus, the correct order of basicity is I > III > II > IV.