| Amongst the acids, |
| (i)\[CH\equiv CCOOH\] |
| (ii)\[C{{H}_{2}}=CHCOOH\]and |
| (iii)\[C{{H}_{3}}C{{H}_{2}}COOH,\] |
| the acid strength follows the sequence |
A) (i) < (ii) > (iii)
B) (i) > (ii) > (iii)
C) (i) = (ii) = (iii)
D) (i) = (ii) > (iii)
Correct Answer: B
Solution :
[b]: Since sp-hybridized carbon is more electronegative than a \[s{{p}^{2}}\text{-}\]hybridized carbon which in turn is more electronegative than \[s{{p}^{3}}\text{-}\] -hybridized carbon, therefore, \[CH\equiv \overset{sp}{\mathop{C}}\,-COOH\] is a stronger \[s{{p}^{2}}\]acid than \[C{{H}_{2}}=\overset{s{{p}^{2}}}{\mathop{C}}\,H-COOH\]which in turn, is a \[s{{p}^{3}}\] stronger acid than \[C{{H}_{2}}=\overset{s{{p}^{2}}}{\mathop{C}}\,H-COOH\]. Thus, the overall order of acid strength is (i) > (ii) > (iii).
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