A) \[\frac{y}{2}\]
B) \[\frac{y}{4}\]
C) y
D) 2y
Correct Answer: C
Solution :
[c] : No. of moles of \[A=\frac{x}{40}\] No. of atoms of \[A=\frac{x}{40}\times {{N}_{A}}=y\] No. of moles of\[B=\frac{2x}{80}=\frac{x}{40}\] Now, no. of atoms of\[B=\frac{x}{40}\times {{N}_{A}},\]i.e., yYou need to login to perform this action.
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