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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 24

  • question_answer
    A physical quantity P is given by \[P=\frac{{{A}^{3}}{{B}^{\frac{1}{2}}}}{{{C}^{-\,4}}{{D}^{\frac{3}{2}}}}\]. The quantity which brings in the maximum percentage error in P is

    A) A                     

    B) B       

    C) C                     

    D)        D

    Correct Answer: C

    Solution :

    Quantity C has maximum power. So it brings maximum error in P.


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