(i) \[90{}^\circ \]if\[{{C}^{2}}={{A}^{2}}+{{B}^{2}}\] |
(ii) greater than \[90{}^\circ \] if \[{{C}^{2}}<{{A}^{2}}+{{B}^{2}}\] |
(iii) greater than \[90{}^\circ \] if \[{{C}^{2}}>{{A}^{2}}+{{B}^{2}}\] |
(iv) less than \[90{}^\circ \]if \[{{C}^{2}}>{{A}^{2}}+{{B}^{2}}\] |
A) (i), (ii) and (iii)
B) (i), (ii) and (iv)
C) (iii) and (iv)
D) (ii) and (iii)
Correct Answer: B
Solution :
[b] From the addition of two vectors, we know that \[{{C}^{2}}={{A}^{2}}+{{B}^{2}}+2AB\,\,\cos \theta \] From this expression, it is clear that \[{{C}^{2}}={{A}^{2}}+{{B}^{2}}\] when \[\theta =90{}^\circ \] \[{{C}^{2}}<{{A}^{2}}+{{B}^{2}}\] when \[\theta >90{}^\circ \] and \[{{C}^{2}}>{{A}^{2}}+{{B}^{2}}\] when \[\theta <90{}^\circ \]You need to login to perform this action.
You will be redirected in
3 sec