A) \[0\]
B) \[\infty \] (Infinity)
C) \[\left( \frac{4\pi {{\varepsilon }_{0}}m{{v}^{2}}}{{{q}^{2}}} \right){{r}^{2}}\]
D) r
Correct Answer: C
Solution :
[c] Radius of curvature \[=\frac{{{v}^{2}}}{{{a}_{1}}}=\left( \frac{4\pi {{\varepsilon }_{0}}m{{v}^{2}}}{{{q}^{2}}} \right){{r}^{2}}\]You need to login to perform this action.
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