A) \[2.01 \times 1{{0}^{-}}^{21}\,kg m\,\,se{{c}^{-}}^{1}\]
B) \[2.01 \times 1{{0}^{-}}^{24}\,g m\,\,se{{c}^{-}}^{1}\]
C) \[2.01 \times 1{{0}^{-}}^{21}\,g m\,\,se{{c}^{-}}^{1}\]
D) \[2.01 \times 1{{0}^{-}}^{24}\,kg m\,\,se{{c}^{-}}^{1}\]
Correct Answer: D
Solution :
\[\lambda =\frac{h}{m\nu }\] \[\therefore \,\,\,\,m\nu =\frac{h}{\lambda }=\frac{6.625\times {{10}^{-\,34}}}{0.33\times {{10}^{-9}}}=2.01\times {{10}^{-24}}kg\,\,m\,\,{{\sec }^{-1}}\]
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