JEE Main & Advanced Sample Paper JEE Main - Mock Test - 25

  • question_answer
    \[\underset{x\to \infty }{\mathop{\lim }}\,{{\left( \frac{{{x}^{2}}+5x+3}{{{x}^{2}}+x+3} \right)}^{x}}=\]

    A) \[{{e}^{4}}\]              

    B) \[{{e}^{3}}\]

    C) \[{{e}^{2}}\]              

    D) e

    Correct Answer: A

    Solution :

    [a] : \[\underset{x\to \infty }{\mathop{\lim }}\,{{\left( \frac{{{x}^{2}}+5x+3}{{{x}^{2}}+x+3} \right)}^{x}}({{1}^{\infty }}form)\] \[=\exp \left\{ \underset{x\to \infty }{\mathop{\lim }}\,\left( \frac{{{x}^{2}}+5x+3}{{{x}^{2}}+x+3}-1 \right)x \right\}\] \[=\exp \left\{ \underset{x\to \infty }{\mathop{\lim }}\,\frac{4{{x}^{2}}}{{{x}^{2}}+x+3} \right\}={{e}^{4}}\]


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