A) Injective but not surjective
B) Bijective
C) Neither injective nor surjective
D) Surjective but not injective
Correct Answer: D
Solution :
[d] \[f(x)=4{{x}^{3}}-12x\] \[\therefore \,\,\,\,\,\,f'(x)=12({{x}^{2}}-1)=12(x+1)(x-1)\] Sign scheme of \[f'(x)\] is as shown in the following figure:You need to login to perform this action.
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