A) \[\frac{1}{\sqrt{3}}\]
B) \[\frac{2}{\sqrt{3}}\]
C) \[\sqrt{3}\]
D) \[2\]
Correct Answer: B
Solution :
[b] Equation of plane through the line \[y+z=2,\] \[x=0\]is: \[(y+z-2)+\lambda x=0\] ...(1) This plane is parallel to the line \[x-z=2,\] \[y=0\] So, plane (1) is perpendicular to the planes \[x-z=0\]and \[y=0\] \[\therefore \,\,\lambda +0-1=0=0\] or \[\lambda =1\] Therefore, equation of plane is: \[y+z-2-x=0\] or \[x-y-z+2=0\] Distance of this plane from origin \[=\frac{2}{\sqrt{3}}\].You need to login to perform this action.
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