A) \[4\]
B) \[5\]
C) \[6\]
D) \[7\]
Correct Answer: C
Solution :
[c] \[{{\log }_{|{{x}^{2}}-1|}}|x-3|\] is defined when \[x-3\ne 0\] and \[|{{x}^{2}}-1|>0\] and \[|{{x}^{2}}-1|\,\,\ne \,\,1.\] \[\Rightarrow \,\,\,x\ne 3,\,\,{{x}^{2}}-1\ne 0\] i.e., \[x\ne 1\] or \[-1\] \[|{{x}^{2}}-1|\,\,\ne 1\Rightarrow x\ne -\sqrt{2}\] or \[\sqrt{2};\] \[x\ne 0\] Therefore, the points at which the function is not defined are \[x=0,\,1,-1,\sqrt{2},-\sqrt{2},3.\]You need to login to perform this action.
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