JEE Main & Advanced Sample Paper JEE Main - Mock Test - 27

  • question_answer
    The amplitude of the electric field in a parallel beam of light of intensity \[2.0\text{W}{{\text{m}}^{-2}}\]is

    A) \[38.8N\,{{C}^{-1}}\]  

    B) \[49.5N\,{{C}^{-1}}\]

    C) \[32.7N\,{{C}^{-1}}\]  

    D) \[35.5N\,{{C}^{-1}}\]

    Correct Answer: A

    Solution :

    [a] : The intensity of a plane electromagnetic wave is \[I={{u}_{av}}c=\frac{1}{2}{{\varepsilon }_{0}}E_{0}^{2}c\] or\[{{E}_{0}}=\sqrt{\frac{2I}{{{\varepsilon }_{0}}c}}=\sqrt{\frac{2\times 2.0}{8.85\times {{10}^{-12}}\times 3\times {{10}^{8}}}}\] \[=38.8N{{C}^{-1}}\]


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