A) 0.4 and 1200 kHz, 990 kHz
B) 0.5 and 1010 kHz, 990 kHz
C) 0.2 and 1010 kHz, 1000 kHz
D) 0.5 and 1500 kHz, 1000 Hz
Correct Answer: B
Solution :
[b]: Modulation index,\[\mu =\frac{{{A}_{m}}}{{{A}_{c}}}\] Side band frequencies are \[USB={{\upsilon }_{c}}+{{\upsilon }_{m}},LSB={{\upsilon }_{c}}-{{\upsilon }_{m}}\] Here,\[{{A}_{m}}=10V,{{A}_{c}}=20V\] \[{{\upsilon }_{c}}=1MHz=1000kHz,{{\upsilon }_{m}}=10kHz\] \[\therefore \]\[\mu =\frac{10}{20}=0.5\] \[USB=1000+10=1010\text{ }kHz,\] \[LSB=1000-10=990\text{ }kHz\]
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