JEE Main & Advanced Sample Paper JEE Main - Mock Test - 27

  • question_answer
    If \[\operatorname{f}:R\to R\] and \[g:R\to R\] are defined by \[f(x)=\left| x \right|\] and \[g(x)=\left[ x-3 \right]\] for \[x\in R\] then \[\left\{ g(f(x)):-\frac{8}{5}<x<\frac{8}{5} \right\}\] is equal to

    A) {0, 1}             

    B)   {1, 2}

    C)   {-3, -2}                       

    D)   {2, 3}

    Correct Answer: C

    Solution :

    Given, \[\operatorname{f}(x)=\,\,\left| x \right|\,\,and g(x)=\,\,\left[ x\,-3 \right]\] For \[-\frac{8}{5}<x<\frac{8}{5};\,\,\,0\le \,\,f\,(x)<\frac{8}{5}\] Now, for \[0\le f(x)<1,\] \[g(f(x))=[f(x)-3]=-\,3[\because \,\,\,-3\le f(x)-3<-\,2]\] \[\operatorname{for}\,\,1\le f(x)<1.6\] \[\operatorname{g}(f(x))=-\,2\,\,\,\,\,\,\,\,\,\,[\because \,\,-2\,\le \,\,f(x)-\,3\,<\,-1.4]\] \[\therefore \,\, required set is \left\{ -3,\,\,-2 \right\}.\]


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