A) \[\frac{13}{6}\]
B) \[\frac{13}{2}\]
C) \[\frac{13}{5}\]
D) \[\frac{13}{7}\]
Correct Answer: A
Solution :
\[\operatorname{y}=1+4x-{{x}^{2}}=5-{{\left( x-2 \right)}^{2}}\] We have \[\int\limits_{0}^{3/2}{\left( 1+4x\,-{{x}^{2}} \right)dx=\,\,2} \int\limits_{0}^{3/2}{mx\,dx}\] \[=\,\,\frac{3}{2}+2\left( \frac{9}{4} \right)-\frac{1}{3}\left( \frac{27}{8} \right)=m\cdot \frac{9}{4}\] On solving we get \[\operatorname{m} = \frac{13}{6}\]You need to login to perform this action.
You will be redirected in
3 sec