A) \[800\overset{\text{o}}{\mathop{\text{A}}}\,\]
B) \[825\overset{\text{o}}{\mathop{\text{A}}}\,\]
C) \[875\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) \[1025\overset{\text{o}}{\mathop{\text{A}}}\,\]
Correct Answer: C
Solution :
Number of possible spectral lines emitted when an electron jumps back to ground state from n111 \[orbit=\frac{n(n-1)}{2}\] \[\frac{n(n-1)}{2}=6\,\,\,\Rightarrow \,\,n=4\] Wavelength \[\lambda \] from transition from \[\operatorname{n} = 1\] to \[\operatorname{n} = 4\] is given by, \[\frac{1}{\lambda }=R\left( \frac{1}{1}-\frac{1}{{{4}^{2}}} \right)\,\,\,\Rightarrow \,\,\lambda =\frac{16}{15R}=\,\,975\overset{{}^\circ }{\mathop{A}}\,\]
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