A) \[\sqrt{2gh+{{u}^{2}}}:u\]
B) \[1:2\]
C) \[1:1\]
D) \[\sqrt{2gh+{{u}^{2}}}:\,\,\sqrt{2\,gh}\]
Correct Answer: C
Solution :
When particle thrown in vertically downward direction with velocity u then final velocity at the ground level. \[{{\operatorname{v}}^{2}}={{u}^{2}}+2gh\,\,\,\,\,\,\therefore \,\,v\,\,=\,\,\sqrt{{{u}^{2}}+2gh}\] Another particle is thrown horizontally with same velocity then velocity of particle at the surface of earth. \[Horizontal\,\,component\,\,of\,\,velocity\,\,{{v}_{x}}=u\] \[\therefore \,\,\,\,Resultant\,\,velocity,\,\,\,\,\nu \,\,={{u}^{2}}\,\,+\,\,2gh\] For both the particles, final velocities when they reach the earth?s surface are equal.You need to login to perform this action.
You will be redirected in
3 sec