A) \[-1/2\]
B) \[0\]
C) \[1/2\]
D) None of these
Correct Answer: D
Solution :
[d] \[f(x)\]is continuous at\[x=1\]. \[\therefore \,\,\,\,\,f({{1}^{-}})=f({{1}^{+}})\] \[\Rightarrow \,\,\,\,\,\,3-2k-2=0\] \[\Rightarrow \,\,\,\,\,\,\,k=\,{{\,}^{\frac{1}{2}}}\] Clearly, \[f(x)\] is not differentiable at\[x=1\].You need to login to perform this action.
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