A) 0.5 and 0.6
B) 0.4 and 0.3
C) 0.6 and 0.6
D) 0.6 and 0.5
Correct Answer: D
Solution :
[d]: Let \[{{\mu }_{s}}\]and\[{{\mu }_{k}}\]be the coefficients of static and kinetic friction between the box and the plank respectively. When the angle of inclination \[\theta \]reaches \[30{}^\circ \], the block just slides, \[\therefore \]\[{{\mu }_{s}}=\tan \theta =\tan {{30}^{o}}=\frac{1}{\sqrt{5}}=0.6\] If a is the acceleration produced in the block, thenYou need to login to perform this action.
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